TOPIC
Wrong answer (100%) ja refiz e nao encontro o err
jvvitral asked 2 years ago
var input = require('fs').readFileSync('/dev/stdin', 'utf8');
var lines = input.split('\n');
var entrada = lines.shift().split(" ", 3)
var limpo = []
limpo[0] = Number(entrada[0])
limpo[1] = Number(entrada[1])
limpo[2] = Number(entrada[2])
if(limpo[0] >= limpo[1] && limpo[0] >= limpo[2]){
var A = limpo[0]
if(limpo[1] > limpo[2]){
var B = limpo[1]
var C = limpo[2]
}
else if(limpo[1]==limpo[2]){
var B = limpo[1]
var C = limpo[2]
}
else{
var B = limpo[2]
var C = limpo[1]
}
}
else if(limpo[1] >= limpo[0] && limpo[1] >= limpo[2]){
var A = limpo[1]
if(limpo[0] > limpo[2]){
var B = limpo[0]
var C = limpo[2]
}
else if(limpo[0]==limpo[2]){
var B = limpo[1]
var C = limpo[2]
}
else{
var B = limpo[2]
var C = limpo[1]
}
}
else if(limpo[2] >= limpo[0] && limpo[2] >= limpo[1]){
var A = limpo[2]
if(limpo[0] > limpo[1]){
var B = limpo[0]
var C = limpo[1]
}
else if(limpo[0]==limpo[1]){
var B = limpo[0]
var C = limpo[1]
}
else{
var B = limpo[1]
var C = limpo[0]
}
}
if(A >= B+C){
console.log("NAO FORMA TRIANGULO")
}
else{
if(A*A==B*B+C*C){
console.log("TRIANGULO RETANGULO")
}
if(A*A > B*B + C*C){
console.log("TRIANGULO OBTUSANGULO")
}
if(A*A < B*B + C*C){
console.log("TRIANGULO ACUTANGULO")
}
if(A==B && B==C ){
console.log("TRIANGULO EQUILATERO")
}
if(A==B || B==C || A==C){
if(A==B && B==C){
}
else{
console.log("TRIANGULO ISOSCELES")
}
}
}