TOPIC
40 % de erro no codigo
ylima11 asked 5 years ago
int main() {
int X;
int soma;
int i=0;
int an;
int resto;
int x[i];
int a;
while(1){
scanf("%d",&X);
if (X==0)
break;
resto = X % 2;
if (resto==0){
an = X +(4)*2;
soma = (an + X)*2.5f;
x[i] = soma;
i=i+1;
//printf("\n%d\n", soma);
}else{
an = X+1+(4)*2;
soma = (an + X+1)*2.5f;
//printf("\n%d\n", soma);
x[i] = soma;
i=i+1;
}
}
for(a=0; a<i;a++){
printf("\n%d", x[a]);
}
}