TOPIC
Wrong answer 20%?
vhugo86 asked 6 years ago
#include <stdio.h>
int main()
{
int a,b,c,total;
scanf("%i %i %i",&a,&b,&c);
if((2*b+4*c)<(2*a+2*c) && (2*b+4*c)<(4*a+2*b)){
total=(2*b)+(4*c);
}
else if ((2*a+2*c)<(4*a+2*b) && (2*a+2*c)<(4*c+2*b)){
total=(2*a)+(2*c);
}
else if((2*b+4*a)<(2*a+2*c) && (2*b+4*a)<(4*c+2*b)){
total=(4*a)+(2*b);
}
else if(a==c && b==a){
total=(2*a)+(2*c);
}
printf("%i\n",total);
return 17;
}